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StronglyTypedUid
C# Implementation of Strongly Typed Id made easy.
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All strongly typed ids are source generated, you must create a record struct in this ways:
Using attribute decorating a record struct (default Guid version)
[StronglyTypedUid]
public readonly partial record struct CustomerId { }
If you want change to Ulid
[StronglyTypedUid(asUlid:true)]
public readonly partial record struct CustomerId { }
Create additional converters to popular packages like efcore, dapper and newtonsoftjson
[StronglyTypedUid(asUlid:true, [EnumAdditionalConverters.EFCore, EnumAdditionalConverters.Dapper, EnumAdditionalConverters.NewtonsoftJson])]
public readonly partial record struct CustomerId { }
The generator will create a partial record struct of the same name
// Auto generated code
[TypeConverter(typeof(CustomerIdTypeConverter))]
[System.Text.Json.Serialization.JsonConverter(typeof(CustomerIdJsonConverter))]
public readonly partial record struct CustomerId(Guid Value) : IStronglyTypedGuid
{
public static CustomerId Empty => new(Guid.Empty);
public static CustomerId NewCustomerId() => new(Guid.NewGuid());
public static implicit operator CustomerId(Guid value) => new(value);
public static explicit operator Guid(CustomerId value) => value.Value;
public bool IsEmpty => Value == Guid.Empty;
public override string ToString() => Value.ToString();
public static CustomerId Parse(string text) => new CustomerId(Guid.Parse(text));
public static bool TryParse(string text, out CustomerId result)
{
try
{
if (Guid.TryParse(text, out Guid uid))
{
result = uid;
return true;
}
}
catch (Exception)
{
}
result = default;
return false;
}
}
You can add additional logic to your strongly type id.
[StronglyTypedUid]
public readonly partial record struct CustomerId
{
public override string ToTaggedString() => $"CID-{Value}";
public static bool TryParseTagged(string text, out CustomerId customer)
{
try
{
if (Guid.TryParse(text[4..], out Guid result))
{
customer = result;
return true;
}
}
catch (Exception)
{
}
customer = default;
return false;
}
}
The new type is decorated with a TypeConverter and a JsonConverter automatically
[TypeConverter(typeof(CustomerIdTypeConverter))]
[System.Text.Json.Serialization.JsonConverter(typeof(CustomerIdJsonConverter))]
You can serialize and deserialize without problems
public record Customer(CustomerId Id, string Name);
var newcustomer = new Customer(CustomerId.NewCustomerId(), "Jhon");
var serializeOptions = new JsonSerializerOptions
{
WriteIndented = true
};
var json = JsonSerializer.Serialize(newcustomer, serializeOptions);
var newcustomer2 = JsonSerializer.Deserialize<Customer>(json);