Awesome

gulp-sloc2

A port of the grunt-sloc plugin for gulp with some minor changes.

Usage

First install the gulp-sloc2 plugin as a development dependency:

npm install --save-dev gulp-sloc2

Then, add it to your gulpfile.js:

var sloc = require('gulp-sloc2');

gulp.task('sloc', function(){
  gulp.src(['scripts/*.js'])
    .pipe(sloc());
});

This would output the following:

[gulp] -------------------------------
[gulp]         physical lines : 135
[gulp]   lines of source code : 97
[gulp]          total comment : 5
[gulp]             singleline : 5
[gulp]              multiline : 0
[gulp]                  empty : 33
[gulp]
[gulp]   number of files read : 2
[gulp]            strict mode
[gulp] -------------------------------

API

sloc(options)

options.tolerant

Type: Boolean, Default: false

Set as false to analyze only files with a subset of popular extensions. true to analyze files with any file extension. The default is false.

If true, the SLOC will be executed on all of the files specified, regardless of file extension. With tolerant set to false, or unspecified, only supported file extensions will be analyzed.

options.reportType

Type: String, Default: stdout

It will generate a JSON file with the SLOC analysis results and sends it further downstream. Use with the reportFile option if you want to customize the file name. You may want to pipe to the gulp.dest() method to write it out to specified folder. Example:

var sloc = require('gulp-sloc2');

gulp.task('sloc', function(){
  gulp.src(['lib/**/*.js'])
    .pipe(sloc({
      reportType: 'json'
    }))
    .pipe(gulp.dest('./reports/'));
});

Would output the following in the file ./reports/sloc.json:

{"total":138,"source":100,"comment":5,"single":5,"block":0,"empty":33,"file":2}

options.reportFile

Type: String, Default: sloc.json

The name of the file which would contain you'd like to output the JSON file. Use with the json as reportType. Ignored if used with the stdout report type. Example:

var sloc = require('gulp-sloc2');

gulp.task('sloc', function(){
  gulp.src(['./test/**/*.js'])
    .pipe(sloc({
      reportType: 'json',
      reportFile: 'testSloc.json'
    }))
    .pipe(gulp.dest('./reports/'));
});

Would output the sloc results in the file ./reports/testSloc.json.

options.reportElements

Type: Object, Default:

{
  before: '-------------------------------',
  after: '-------------------------------',
  mode: true
}

Options used to customize output message. Use with the stdout as reportType. Ignored if used with the json report type.

before - Line printed before report. Set to false to disable line before report.
after - Line printed after report. Set to false to disable line after report.
mode - Print strict/tolerant mode information if true.

options.metrics

Type: Array[String], Default: ['total', 'source', 'comment', 'single', 'block', 'mixed', 'empty', 'file']

Metrics that are returned in report.

Supported Languages and Extensions

JavaScript - js
CoffeeScript - coffee or coffeescript
C / C++ - c or cc
Python - py
Java - java
PHP - php

FAQ

I'm getting a TypeError: Cannot read property 'toString' of null;.

You probably have folders in your stream and sloc tries to read their contents. Change this:
```
  gulp.src(['src/**']).pipe(sloc())
  
```
To this:
```
  gulp.src(['src/**'], {nodir: true}).pipe(sloc())
  
```

Contributing

Fork it
Create your feature branch (git checkout -b my-new-feature)
Commit your changes (git commit -am 'Add some feature')
Push to the branch (git push origin my-new-feature)
Create new Pull Request