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datkt.flattree

Port of @mafintosh's flat-tree functions to map a binary tree to a list.

Installation

The datkt.flattree package an be installed with NPM.

$ npm install @datkt/flat-tree

Prerequisites

Usage

## Compile a program in 'main.kt' and link flat-tree libraries found in `node_modules/`
$ konanc main.kt $(konanc-config -clr @datkt/flat-tree) -o main.kexe
$ ./main.kexe

where main.kt might be

import datkt.flattree.*

fun main(args: Array<String>) {
  val tree = Tree()
  tree.parent(0L, null) // 1L
  tree.parent(2L, null) // 1L
  tree.parent(1L, null) // 3L
}

API

index = ftIndex(depth: Long, offset: Long): Long

Returns an array index for the tree element at the given depth and offset

parentIndex = tree.parent(index: Long, depth: Long?): Long

Returns the index of the parent element in tree

siblingIndex = tree.sibling(index: Long, depth: Long?): Long

Returns the index of this elements sibling

children = tree.children(index: Long, depth: Long?): Array<Long>

Returns an array [leftChild, rightChild] with the indexes of this elements children. If this element does not have any children it returns null

range = tree.spans(index: Long, depth: Long?): Array<Long>

Returns the range (inclusive) the tree root at index spans. For example tree.spans(3) would return [0, 6] (see the usage example).

index = tree.leftSpan(index: Long, depth: Long?): Long

Returns the left spanning in index in the tree index spans.

index = tree.rightSpan(index: Long, depth: Long?): Long

Returns the right spanning in index in the tree index spans.

count = tree. count(index: Long, depth: Long?): Long

Returns how many nodes (including parent nodes) a tree contains

depth = ftDepth(index: Long): Long

Returns the depth of an element

offset = ftOffset(index: Long, depth: Long?): Long

Returns the relative offset of an element

roots = tree.fullRoots(index: Long, result: Array<Long>?): Array<Long>

Returns a list of all the full roots (subtrees where all nodes have either 2 or 0 children) < index. For example fullRoots(8) returns [3] since the subtree rooted at 3 spans 0 -> 6 and the tree rooted at 7 has a child located at 9 which is >= 8.

index = iterator.next(): Long

Move the iterator the next item in the tree.

index = iterator.prev(): Long

Move the iterator the prev item in the tree.

iterator.seek(index: Long)

Move the iterator the this specific tree index.

index = iterator.parent(): Long

Move the iterator to the current parent index

index = iterator.leftChild(): Long

Move the iterator to the current left child index.

index = iterator.rightChild(): Long

Move the iterator to the current right child index.

index = iterator.leftSpan(): Long

Move the iterator to the current left span index.

index = iterator.rightSpan(): Long

Move the iterator to the current right span index.

bool = iterator.isLeft(): Boolean

Is the iterator at a left sibling?

bool = iterator.isRight(): Boolean

Is the iterator at a right sibling?

index = iterator.sibling(): Long

Move the iterator to the current sibling

See Also

License

MIT