Awesome
igor
igor (pronounced eye-gor) is a small, unpretentious, self-contained and header-only C++17 library implementing named function arguments (AKA keyword arguments, named parameters, etc.). A minimal example:
#include <iostream>
#include <string>
#include <igor/igor.hpp>
using namespace igor;
// Create a named argument called "arg1".
inline constexpr auto arg1 = named_argument<struct arg1_tag>{};
// You can also use a macro (ew, gross!).
IGOR_MAKE_NAMED_ARGUMENT(arg2);
// A variadic function accepting named arguments.
template <typename ... Args>
auto adder(Args && ... args)
{
parser p{args...};
return p(arg1) + p(arg2);
}
int main()
{
using namespace std::literals;
std::cout << adder(arg1 = "hello, "s, arg2 = "world") << '\n';
std::cout << "The ultimate answer is: " << adder(arg2 = 20, arg1 = 22) << '\n';
return 0;
}
igor is partly inspired by Python's kwargs
machinery, and it is meant for use in conjunction with
variadic templates. If you cannot (or do not want to) use templates, igor might not be the best fit
for your needs, and you might want to investigate other libraries such as
Boost.Parameter or
argo.
How does it work?
A parser
object identifies named arguments upon construction, and stores internally
references to the values associated to the named arguments. Later, these references can be fecthed via
parser
's call operator. Named arguments can be passed in any order and they can be associated to values
of any type.
How do I check which named arguments were provided?
Like this:
template <typename ... Args>
void arg_check(Args && ... args)
{
parser p{args...};
if (p.has(arg1)) {
std::cout << "arg1 was provided\n";
} else {
std::cout << "arg1 was NOT provided\n";
}
if (p.has(arg2)) {
std::cout << "arg2 was provided\n";
} else {
std::cout << "arg2 was NOT provided\n";
}
}
If a named argument is not provided, parser
's call operator will return
a const
reference to a global object of the special type not_provided_t
:
#include <cassert>
#include <type_traits>
template <typename ... Args>
void missing_arg(Args && ... args)
{
parser p{args...};
// Look ma, structured bindings!
auto [a, b] = p(arg1, arg2);
if (!p.has(arg1)) {
assert(std::is_same_v<decltype(a), const not_provided_t &>);
}
}
How do I use igor in generic code?
igor is if constexpr
friendly, thus you can easily do compile-time dispatching based on the
presence of a specific named argument and/or its type:
#include <iostream>
#include <string>
#include <type_traits>
// Handy alias.
template <typename T>
using uncvref_t = std::remove_cv_t<std::remove_reference_t<T>>;
template <typename ... Args>
void arg_dispatch(Args && ... args)
{
parser p{args...};
auto [a, b] = p(arg1, arg2);
if constexpr (p.has(arg1)) {
if constexpr (std::is_same_v<uncvref_t<decltype(a)>, int>) {
std::cout << "arg1 is an int. arg1 + 2 is: " << (a + 2) << ".\n";
} else if constexpr (std::is_same_v<uncvref_t<decltype(a)>, std::string>) {
std::cout << "arg1 is a string. arg1 has a size of " << a.size() << ".\n";
} else {
std::cout << "arg1 is some type other than int or string.\n";
}
}
}
Does it work with move-only types?
Yes. A parser
perfectly forwards references to the values associated to named arguments, and thus you
are free to use std::move()
and std::forward()
as you like. For instance:
#include <utility>
struct move_only
{
move_only() = default;
move_only(move_only &&) = default;
// Remove the copy constructor.
move_only(const move_only &) = delete;
};
template <typename ... Args>
void move_argument(Args && ... args)
{
parser p{args...};
move_only inner{std::move(p(arg1))};
}
int main()
{
move_only mo;
move_argument(arg1 = std::move(mo));
move_argument(arg1 = move_only{});
}
An example of perfect forwarding:
#include <utility>
template <typename T, typename U>
void inner_function(T &&x, U &&y)
{
// Do something with x and y...
}
template <typename ... Args>
void outer_function(Args && ... args)
{
parser p{args...};
auto [a, b] = p(arg1, arg2);
inner_function(std::forward<decltype(a)>(a), std::forward<decltype(b)>(b));
}
int main()
{
outer_function(arg2 = 3, arg1 = 6.7);
}
Does it work with std::initializer_list
?
Yes it does:
#include <initializer_list>
template <typename ... Args>
void init_list(Args && ... args)
{
parser p{args...};
auto [a, b] = p(arg1, arg2);
std::cout << "First init list: ";
for (auto v: a) {
std::cout << v << " ";
}
std::cout << "\nSecond init list: ";
for (auto v: b) {
std::cout << v << " ";
}
std::cout << '\n';
}
int main()
{
init_list(arg1 = {1, 2, 3}, arg2 = {"a", "b", "c"});
}
How does the assembly look?
Pretty good. One of igor's design goals is to make the handling of named arguments as efficient
as possible. Ideally, functions with and without named arguments should compile to identical binary code.
You can see that, at least in a couple of simple examples, this is indeed the case: https://godbolt.org/z/c3r9xa
(e.g., look for the add_int()
and add_int_igor()
functions in the generated assembly).
I am convinced. How do I get it?
If you are in a hurry, just download igor.hpp
and chuck it somewhere. igor depends only on the standard library and it
is contained in a single header file.
Otherwise, you can install it via the usual CMake spells.
Why "igor"?
Igor is the trusty manservant of Dr. Frankenstein (pronounced Fronkonsteen) in the 1974 comedy classic "Young Frankenstein".
Or perhaps it is a reference to Igor Stravinsky.